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post #21 of Old 02-22-2007
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Ok, so this is simpler than I first thought. This is way I should have done it the first time.

First of all, this is the situation. The distance the friendís boat will travel is 5t (t = hours) NM on a course of 036 Deg T. You are 84NM from him at a bearing of 096 Deg T relative to his boat. In order to meet, you will travel a distance of 7t NM at some unknown heading.

Itís obvious that the angle between the track of your friendís boat and the bearing from his boat to yours is 96 Ė 36 = 60 Deg

Remember the law of sines? Itís handy. It says that for any triange the ratios of the length of each side to the angle opposite that side are equal.

If A is the angle between the heading you need and the bearing from your boat to your friends,

that means: sin60 / 7t = sinA / 5t

or sin Ė1 (5/7 * sin 60) = A

A = 38.2 Deg

Your heading then should be 96 + 38.2 + 180 = 314.2 Deg T

How long to get there?

We all remember that the sum of all the internal angles of a triangle = 180 so the remaining angle is 180 Ė 38.2 Ė 60 = 81.8 Deg

From the law of sines, 7t = 84 * sin 60 / sin 81.8

t =10.5 hours

There are 10 kinds of people. Those who understand binary and those who don't.

Last edited by CapnHand; 02-22-2007 at 09:22 PM.
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