Ok, so this is simpler than I first thought. This is way I should have done it the first time.
First of all, this is the situation. The distance the friend’s boat will travel is 5t (t = hours) NM on a course of 036 Deg T. You are 84NM from him at a bearing of 096 Deg T relative to his boat. In order to meet, you will travel a distance of 7t NM at some unknown heading.
It’s obvious that the angle between the track of your friend’s boat and the bearing from his boat to yours is 96 – 36 = 60 Deg
http://www.sailnet.com/photogallery/...ll=no&dthumbs=
Remember the law of sines? It’s handy. It says that for any triange the ratios of the length of each side to the angle opposite that side are equal.
If A is the angle between the heading you need and the bearing from your boat to your friends,
that means: sin60 / 7t = sinA / 5t
or sin –1 (5/7 * sin 60) = A
A = 38.2 Deg
Your heading then should be 96 + 38.2 + 180 = 314.2 Deg T
How long to get there?
We all remember that the sum of all the internal angles of a triangle = 180 so the remaining angle is 180 – 38.2 – 60 = 81.8 Deg
From the law of sines, 7t = 84 * sin 60 / sin 81.8
t =10.5 hours
__________________
There are 10 kinds of people. Those who understand binary and those who don't.
Last edited by CapnHand; 02222007 at 09:22 PM.
