SailNet Community - View Single Post - Navigation Questions. Can you do them?
View Single Post
Old 02-26-2010
scraph scraph is offline
Senior Member
Join Date: Oct 2009
Posts: 167
Thanks: 0
Thanked 0 Times in 0 Posts
Rep Power: 6
scraph is on a distinguished road
009°T is 67°R (forward the starboard beam)
158°T is 216°R (port quarter)
328°T is 26°R (off the starboard bow)

The site is correct. What you want to do with the given information is: TB - SH = RB. If the result is negative, you can either consider it an angle towards port (clockwise) or you can add 360° to normalize it to a standard 0°-360° angle.
1981 C&C 32
Reply With Quote Share with Facebook