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post #1 of 4 Old 07-26-2012 Thread Starter
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fuel consumption

i was searching forum and google could not find so here my "question"

how to convert fuel consumption from g/kWh to Lit/h

should i sum "power kw x g/kwh" multiply or divide by the density of the fuel to get Lit/h

ei.

Fuel consumption 215 g/kWh

Rated power is 100 kW.


At 100 kW, fuel consumptuion is...

215 g/kWh x 100kW = 21500 g/h or 21.500 kg/h

0.85 kg/l is a typical figure for diesel

21.500 kg/h x 1 L/0.85 kg = 18.3 L/h ( 4.025 Imperial gallons or 4.834 US gallons)


should i this "21.500kg/h" multiply or devide by 0.85 to get Lit/h


thanks

Last edited by lola rose; 07-26-2012 at 06:57 AM.
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post #2 of 4 Old 07-26-2012
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fuel consumption

The units have to cancel so it looks like division is what you need as you showed in the example. I'm not sure about the multiplication by rated power however - do you really use that or is it a maximum value?
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post #3 of 4 Old 07-26-2012
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Re: fuel consumption

You have it correct. Multiply by the power in kW then divide by the density in g/l. Note that you if you want consumption at other than rated power, use the actual power and the fuel rate at that power. The fuel rate will vary somewhat with power, though not much once above about 1/3 rated power.
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post #4 of 4 Old 07-27-2012 Thread Starter
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Re: fuel consumption

thanks for your reply. you are correct should be

g/Kwh x engine kw : density of fuel (0.85 for diesel)

one more "question".

can i install 100 US gallon tank in the 20 foot boat. ofcourse, i can. but should it be overkill. engine is FNM HPEP-150 sterndrive. what would be bigest tank that i normaly can install in boat this size. i would like to have as much range as posible.

i am in europe and would like to cruise med, croatia to greece, sicily, etc at least 300 miles range with 10% reserve fuel


thanks one more time.

(sorry for english, it is not my first language)

this is the boat...

Overall Length 20' 3"

Overall Beam 6' 10"



Last edited by lola rose; 07-27-2012 at 01:18 PM.
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