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Oops. Maybe a little stretch goes a long way.
If we treat a 6m long lifeline as a straight line (OK, usually it isn't, but it makes the analysis easier), and we calculate what the deflection would be if we push at the mid-point, then we would basically have two right-triangles. Here the hypotenuse of each of these triangles would be half the stretched length, and the other sides would be half the the original length and the deflection. Solve using Pythagoras, and we wind up with a 30 cm (about a foot) deflection. Hmmm... Might be a bit more than would be considered acceptable. Dux (if I'm doing this right) would have a deflection less than a third as large.
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