Riddles with a Prize, by Mantus Anchors - Page 7 - SailNet Community
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Re: Riddles with a Prize, by Mantus Anchors

The Jack in the Box
Jack weighs m
Box weighs M

So if you depress the head of the Jack and release it suddenly, it will pop up because of the spring between the Jack and the bottom of the box. How much force is required to depress the Jack so that both the Jack and the Box will jump up into the air? The mass of the Jack is m and the mass of the Box is M and the weight of the spring is negligible.
The spring is regular linear spring....

The PRIZE is MANTUS CHAIN HOOK that fits your chain size....
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Re: Riddles with a Prize, by Mantus Anchors

If I recall my phsyics you are requiring or ignoring any number of unbounded assumptions about the nature of the spring itself. So with your unspoken indication that unbounded assumptions are the key to the answer, I can firmly state that no amount of force will ever be sufficient to make the box pop up into the air, as both the box and Jack are hovering in a zero-gravity LaGrange point in earth-lunar orbit. Without an operational gravity field being specified, any force "down" on the spring will simply repel the entire box, Jack and all, away from the pusher, out of the LaGrange point, and eventually to a violent death as it falls into a gravity well and plunges into the surface below, or bursts into flames en route.
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Re: Riddles with a Prize, by Mantus Anchors

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Originally Posted by Mantus Anchors View Post
How much force is required to depress the Jack so that both the Jack and the Box will jump up into the air?
This Force will get Jack into the air...

altho...it might excite him instead of "depress"-ing him - is that allowed?
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Re: Riddles with a Prize, by Mantus Anchors

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If I recall my phsyics you are requiring or ignoring any number of unbounded assumptions about the nature of the spring itself. So with your unspoken indication that unbounded assumptions are the key to the answer, I can firmly state that no amount of force will ever be sufficient to make the box pop up into the air, as both the box and Jack are hovering in a zero-gravity LaGrange point in earth-lunar orbit. Without an operational gravity field being specified, any force "down" on the spring will simply repel the entire box, Jack and all, away from the pusher, out of the LaGrange point, and eventually to a violent death as it falls into a gravity well and plunges into the surface below, or bursts into flames en route.

I like this answer... but If the Box is made by Mantus it will land safely and survive re-entry...
No there is a solution to this problem... that can be expressed in M and m
Greg

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Re: Riddles with a Prize, by Mantus Anchors

I can confirm that Greg ships his anchor in one tough box!
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Re: Riddles with a Prize, by Mantus Anchors

m+2M
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Re: Riddles with a Prize, by Mantus Anchors

not yet...

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Re: Riddles with a Prize, by Mantus Anchors

(m+M)/32
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Re: Riddles with a Prize, by Mantus Anchors

m+M
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Re: Riddles with a Prize, by Mantus Anchors

The ratio of m/M .the acceleration of head and box are the inverse. but I don't know Jack.and to lift the box needs enough force to overcome grav. so the force must be M x9.8 meters per sec squared
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