Join Date: Mar 2006
Location: New England
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For a windlass, you really don't want a 10% voltage drop. It would probably make far more sense to install a battery forward and use a duocharge unit to keep it charged or to go with much heavier wire to provide a 3% voltage drop at a maximum. Providing low voltage to a windlass motor will shorten its lifespan.
BTW, from the lewmar windlass instructions:
Check the voltage across the motor leads with the windlass on. (Proper voltage is 13.5 V. Constant low voltage will destroy the motor)
I am planning to go with AWG 2 for the windlass based on a reportedly fine (by some)10% voltage drop. I may install a battery in the bow as well but am undecided. I am thinking the windlass will run at about 85 amps under normal load?
130 amp, 50’. @ 10%
CM=K x l x L / E
CM = Circular Mil area of Conductors
K = 10.75 (Constant representing the mil-foot resistance of copper)
I = Current - amps
L = Length - feet
E = Voltage drop at load (in volts)
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You know what the first rule of sailing is? ...Love. You can learn all the math in the 'verse, but you take
a boat to the sea you don't love, she'll shake you off just as sure as the turning of the worlds. Love keeps
her going when she oughta fall down, tells you she's hurting 'fore she keens. Makes her a home.
—Cpt. Mal Reynolds, Serenity (edited)
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Last edited by sailingdog; 03-13-2010 at 03:50 PM.